atwood machine problem :?

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72826
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atwood machine problem :?

Post by 72826 »

Well, I ran across this question and my dad and I decided to have at it... It's pretty trivial but we were kinda stuck for a while, and I was wondering if we could have some input... It would be great if we weren't the only ones with these answers...

Q: A simple Atwood's machine uses two masses, m1 and m2. Starting from rest, the speed of the two masses is 3.0 m/s at the end of 3.0 s. At that instant, the kinetic energy of the system is 60 J and each mass has moved a distance of 4.5 m. Determine the values of m1 and m2.

A:
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Where Et = Energy total

ps* We cleaned up the problem a little bit (it took a few pages to answer the question), so this is the nitty gritty of the question, two equations with two unknowns.
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eXg.Ground Zero
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Post by eXg.Ground Zero »

lol Sorry can't help you here :(
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gameover
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Post by gameover »

google is ur frend :P
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Post by 72826 »

eXg.eXuals wrote:google is ur frend :P
That's where I found the question :P No answer though
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>pwrhz< D!ggy
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Post by >pwrhz< D!ggy »

Never have understood that.
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Post by CaMeL »

well, i dont know if i understand correctly but if both masses were traveling the same speed, ended at the same time, and ended up at 4.5m. then I would "guess" that the masses are the same. so i found a combined total of ~13.333 kg, then m1 & m2 both equal 6.6665kg each. I am probably completely wrong. but i wanna know the answer now. lol.
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Post by 72826 »

If the masses were equal then -after starting from rest- this machine would have equal forces acting in opposite directions, therefore no motion after 3 seconds. The fact that it's accelerating 1m/s^2 means one mass (m1) is heavier than the other.
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eXg. Pun1sher
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Post by eXg. Pun1sher »

Do you know what the mass of the pulley is, and do you have to account for the friction of the string ??
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Post by 72826 »

EDIT*** No friction and a massless pulley
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